Question

Factorise step By Step x^2+y^2-z^2-2xy​

Answer 1

Answer:

x^2+y^2-z^2-2xy

=x^2+y^2-2xy-z^2

=(x)^2+(y)^2-2×x×y-z^2

=(x-y)^2-x^2

we know that, (a^2-b^2)= (a+b) (a-b)

so that (x-y)^2-z^2= (x-y+z) (x-y-z)