Question

factorise
$1 + x + xy + {x}^2y{?}$
​

Answer 1

Step-by-step explanation:

$1 + x + xy + {x}^2y{?}$

$(1 + x) + (xy + x {}^{2} y)$

$1(1 + x) + xy(1 + x)$

$(1 + x )(1 + xy)$

Answer 2

Step-by-step explanation:

1 + x + xy + {x}^2y{?}1+x+xy+x2 y?

(1 + x) + (xy + x {}^{2} y)(1+x)+(xy+x2 y)

1(1 + x) + xy(1 + x)1(1+x)+xy(1+x)

(1 + x )(1 + xy)(1+x)(1+xy)

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