Question

factorise
$2 {x}^{2} - 27$
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Answer 1

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Q:-

$2 {x}^{2} - 27$

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$⟹</p><p>2 {x}^{2} - 27$

$⟹</p><p> { (\sqrt{2x} )}^{2} - {(3 \sqrt{3} )}^{2}$

It is the form of a^2-b^2

$⟹</p><p> {a}^{2} - {b}^{2} = (a + b)(a - b)$

$⟹</p><p>So, {( \sqrt{2x} )}^{2} - {(3 \sqrt{3}) }^{2} = ( \sqrt{2}x + 3 \sqrt{3} )( \sqrt{2} x - 3 \sqrt{3} )$

$</p><p>∴2 {x}^{2} - 27 = ( \sqrt{2} x + 3 \sqrt{3} )( \sqrt{2} x - 3 \sqrt{3} )$

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HOPE IT HELPS YOU..

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Thankyou:)

Answer 2

((2^0.5)x + 3(3^0.5)) * ((2^0.5)x-3(3^0.5))