Question

factorise
$2 {x}^{2} + 7x + 3$
by splitting the middle term ​

Answer 1

${2x}^{2} + 7x + 3 \\ = {2x}^{2} + 6x + x + 3 \\ = 2x(x + 3) + 1(x + 3) \\ = (x + 3)(2x + 1)$

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Answer 2

The correct answer is "x= -1/2" and "x= -3".

Step-by-step explanation:

$The \ given \ equation \ is:\\2x^2+7x+3=0\\On \ factorizing \ the \ above \ equation,we \ get\\2x^2+6x+x+3=0\\2x(x+3)+1(x+3)=0\\(2x+1)(x+3)=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2} \\Or,\\x+3=0\\x=-3$

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