Factorise
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Class 9
>>Maths
>>Polynomials
>>Factorisation of Polynomial
>>Using the factor theorem factorise the f
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Using the factor theorem factorise the following polynomial completely 3x
3
+2x
2
−19x+6.
Medium
Solution
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Let f(x)=3x
3
+2x
2
−19x+6
For x=2, the value of f(x) will be,
=3(2)
3
+2(2)
2
−19(2)+6
⇒24+8−38+6=0
According to the factor theorem, (x−a) is a factor of f(x) if f(a)=0
∴ (x−2) is a factor of f(x). [∵ f(2)=0]
Now, performing long division as shown in the above image, we have
f(x)=(x−2)(3x
2
+8x–3)
⇒(x−2)(3x
2
+9x−x−3)
⇒(x−2)[3x(x+3)−1(x+3)]
⇒(x−2)(x+3)(3x−1)
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