Question

Factorise
$3x^3-24y^3/125$
​

Answer 1

$\bold{= 3x^{3} - 1. \frac{ 24y ^{3} }{125}}$

$\bold{= 3x {}^{3} + \frac{1.24y {}^{3} }{125}}$

$\bold{ = {3x}^{3} + \frac{ - 24y {}^{3} }{125}}$