Question

factorise :
$8y {3}^{} - 125x {3}^{}$
​

Answer 1

8y³ - 125x³

(2y)³ - (5x)³

∴ a³ - b³= (a-b) (a² + b² + 2ab)

(2y)³-(5x)³

= (2y - 5x) [(2y)² + (5x)² + 2 . 2y . 5x ]

= (2y - 5x) [4y²+ 25x² + 20xy]

Hope it helps!

Answer 2

hey mate

here is your answer

${8y}^{3} - 125 {x}^{3} = (2y - 5x)( {4y}^{2} + 10xy + {25x}^{2} )$

hope it helps