Math, asked by yusufyunus7989, 9 months ago

FACTORISE
 {a}^{2} +  \frac{1}{ {a}^{2} }  - 2 - 3a +  \frac{3}{a}
make grouping ​

Answers

Answered by Anonymous
10

Answer:

a^2+1/a^2-2-3a+3/a

(a-1/a)^2-3(a-1/a)

(a-1/a)(a-1/a-3)

Answered by Anonymous
91

Given :

  • a² + 1/a² - 2 - 3a + 3/a

Solution :

Apply identity : (a - b)² = a² + b² - 2ab

→ a² + 1/a² - 2 - 3a + 3/a

→ (a)² + (1/a)² - 2 × a × 1/a - 3a + 3/a

→ (a - 1/a)² - 3a + 3/a

Take 3 as a common

→ (a - 1/a)² - 3(a - 1/a)

Now, take (a - 1/a) as a common

→ (a - 1/a)[(a - 1/a) - 3]

→ (a - 1/a)[a - 1/a - 3]

Some Identities :

  • (a + b)² = a² + b² + 2ab
  • (a + b)³ = a³ + b³ + 3ab(a + b)
  • (a - b)³ = a³ - b³ - 3ab(a - b)
  • a² - b² = (a + b)(a - b)
  • a³ - b³ = (a - b)(a² + ab + b²)
  • a³ + b³ = (a + b)(a² - ab + b²)
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