FACTORISE
make grouping
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Answered by
10
Answer:
a^2+1/a^2-2-3a+3/a
(a-1/a)^2-3(a-1/a)
(a-1/a)(a-1/a-3)
Answered by
91
Given :
- a² + 1/a² - 2 - 3a + 3/a
Solution :
Apply identity : (a - b)² = a² + b² - 2ab
→ a² + 1/a² - 2 - 3a + 3/a
→ (a)² + (1/a)² - 2 × a × 1/a - 3a + 3/a
→ (a - 1/a)² - 3a + 3/a
✪ Take 3 as a common ✪
→ (a - 1/a)² - 3(a - 1/a)
✪ Now, take (a - 1/a) as a common ✪
→ (a - 1/a)[(a - 1/a) - 3]
→ (a - 1/a)[a - 1/a - 3]
Some Identities :
- (a + b)² = a² + b² + 2ab
- (a + b)³ = a³ + b³ + 3ab(a + b)
- (a - b)³ = a³ - b³ - 3ab(a - b)
- a² - b² = (a + b)(a - b)
- a³ - b³ = (a - b)(a² + ab + b²)
- a³ + b³ = (a + b)(a² - ab + b²)
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