Question

factorise
$x ^{2} - (1 + \sqrt{2} )x + \sqrt{2}$

Answer 1

HEY HERE IS YOUR ANSWER☺☺☺

${x}^{2} - (1 + \sqrt{2} ) x+ \sqrt{2} \\ \\ {x}^{2} - x - \sqrt{2} x + \sqrt{2} \\ \\ ( {x}^{2} - x) + ( - \sqrt{2} x + \sqrt{2} ) \\ \\ x(x - 1) - \sqrt{2} (x - 1) \\ \\ (x - 1)(x - \sqrt{2} )$

We have factorised in the identity (x +a) (x+b) =x^2 + (a+b)x + ab

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#Aadi 93

Answer 2

!! Hey Mate !!

Your answer is --

we have ,

${x}^{2} - (1 + \sqrt{2} )x + \sqrt{2} \\ \\ = {x}^{2} - x - \sqrt{2} x + \sqrt{2} \\ \\ = x(x - 1) - \sqrt{2} (x - 1) \\ \\ = (x - 1)(x - \sqrt{2} )$


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