factorise
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Hey!!!!
Good Afternoon
______________
We have
=> (x² - 2x)² - 2(x² - 2x) - 3 = 0
let (x² - 2x) = a
Then
=> a² - 2a - 3 = 0
=> a² - 3a + a - 3 = 0 (splitting method)
=> a(a - 3) + (a - 3) = 0
=> (a + 1)(a - 3) = 0
Thus x² - 2x = 3 or x² - 2x = -1
Case 1
=> x² - 2x - 3 = 0
=> (x + 1)(x - 3) = 0
=> x = -1 or x = 3
Case 2
=> x² - 2x + 1 = 0
=> x² - x - x + 1 = 0
=> x(x - 1) - (x - 1) = 0
=> (x - 1)² = 0
=> x = 1 or x = 1
____________
Hope this helps ✌️
Good Afternoon
______________
We have
=> (x² - 2x)² - 2(x² - 2x) - 3 = 0
let (x² - 2x) = a
Then
=> a² - 2a - 3 = 0
=> a² - 3a + a - 3 = 0 (splitting method)
=> a(a - 3) + (a - 3) = 0
=> (a + 1)(a - 3) = 0
Thus x² - 2x = 3 or x² - 2x = -1
Case 1
=> x² - 2x - 3 = 0
=> (x + 1)(x - 3) = 0
=> x = -1 or x = 3
Case 2
=> x² - 2x + 1 = 0
=> x² - x - x + 1 = 0
=> x(x - 1) - (x - 1) = 0
=> (x - 1)² = 0
=> x = 1 or x = 1
____________
Hope this helps ✌️
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