Question

factorise
${x}^{2} + \frac{1}{ {x}^{2} } - 2 - 3x + \frac{3}{x}$

Answer 1

${x}^{2} + \frac{1}{ {x}^{2} } - 2 - 3x + \frac{3}{x} \\ \\ = {(x)}^{2} + {( \frac{1}{x}) }^{2} - 2(x)( \frac{1}{x} ) \: \: \: - 3(x - \frac{1}{x} ) \\ \\ = {(x - \frac{1}{x}) }^{2} - 3(x - \frac{1}{x} ) \\ \\ = (x - \frac{1}{x} )(x - \frac{1}{x} - 3)$

Answer 2

Answer:

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