Question

factorise :
${x}^{2} + \frac{x}{4} - \frac{1}{8}$
​

Answer 1

Hello Nupur !✌

Question:

Factorise

${x}^{2} + \frac{x}{4} - \frac{1}{8}$

Solution:

${x}^{2} + \frac{x}{4} - \frac{1}{8}$

${x}^{2} - \frac{x}{4} + \frac{x}{2} - \frac{1}{8}$

$x(x - \frac{1}{4}) + \frac{1}{2}(x - \frac{1}{4} )$

$(x + \frac{1}{2})(x - \frac{1}{4} )$

Hope this helps

@adiba31❤☺

Answer 2

${x}^{2} + \frac{x}{4} - \frac{1}{8}$

Answer :-

$= 8{x}^{2} + 2x - 1$

$= 8 {x}^{2} + 4x - 2x - 1$

$= 4x(2x + 1) - 1(2x + 1)$

$= (2x + 1)(4x - 1)$

Hope this will help u.