Question

factorise the 3y^2+y^3+3+y​

Answer 1

Answer:

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Step-by-step explanation:

Given that: y3−3y2+2y−6−xy+3x

              =(y3−3y2)+(2y−6)+(−xy+3x),  (group pair of terms)

             =y2(y−3)+2(y−3)−x(y−3), (factor each binomials)

            =(y−3)(y2+2−x) ,  (factor out common factor (y−3))

The common factors of y3−3y2+2y−6−xy+3x are (y−3)(y2+2−x)