Factorise the Algebraic expression
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answer:-
3abc(abc+9a2b2c+27)
Explanation:-
3a2b2c2+27a3b3c2+81abc
3abc(abc+9a2b2c+27) (taking 3abc as common)
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Answer:
3abc (abc + 9a²b²c - 27)
This is the correct answer
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