Question

factorise the attached ​

Answer 1

Answer:

Please mark the answer as brainliest.

Step-by-step explanation:

(a+b)³-8=(a+b)³-2³=(a+b-2)(a²+2ab+b²+2a+2b+4) as a³-b³=(a-b)(a²+2ab+b²)

Answer 2

Answer:

$= {(a + b)}^{3} - 8 \\ \\ = {(a + b)}^{3} - {(2)}^{3} \\ \\ = {(a + b - 2)}^{3} + 6(a + b)(a + b - 2) \\ \\ = (a + b - 2)(( {a + b - 2)}^{2} + 6(a + b)) \\ \\ = (a + b - 2)( { a}^{2} + {b}^{2} + 2ab - 8a - 8b + 6a + 6b) \\ \\ = (a + b - 2)( { a}^{2} + {b}^{2} + 2ab - 2a - 2b)$