factorise the expression 125m cube +64n cube
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=(5m+4n)^3
identity=(a+b)^3
=a^3+b^3+3ab(a+b)
(5m)^3+(4n)^3+3*5m*4n(5m+4n)
125m^3+64n^3+60mn(5m+4n)
125m^3+64n^3+300m^2n+240mn^2
identity=(a+b)^3
=a^3+b^3+3ab(a+b)
(5m)^3+(4n)^3+3*5m*4n(5m+4n)
125m^3+64n^3+60mn(5m+4n)
125m^3+64n^3+300m^2n+240mn^2
Harschaudharygarg:
thanks
Answered by
1
Answer:
(5m+4n)^3
identity=(a+b)^3
=a^3+b^3+3ab(a+b)
(5m)^3+(4n)^3+3*5m*4n(5m+4n)
125m^3+64n^3+60mn(5m+4n)
125m^3+64n^3+300m^2n+240mn^2
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