Question

Factorise the expression 2x^2-4x+5

Answer 1

Answer:

-1+√-24 and-1-√-24

Step-by-step explanation:

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Answer 2

$2x^2-4x+5$ here we cannot split the middle term into two parts, so we apply the discriminant method.

a=2, b=-4 and c=5

$D=b^2-4ac\\=(-4)^2-4\times2\times5\\=16-40\\=-24$

Here, D>0, thus root of the equation is real and distinct.

Thus, root  x are,

$=\frac{-b+\sqrt{D} }{2a} \\=\frac{-(-4)+\sqrt{-24}}{2\times2} \\=\frac{4+\sqrt{-24}}{4}$      and    $=\frac{-b-\sqrt{D} }{2a} \\=\frac{-(-4)-\sqrt{-24}}{2\times2} \\=\frac{4-\sqrt{-24}}{4}$