Factorise the expression (2x - 3y) cube
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Heya!!! User!!! ✌
Here's your answer friend,
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==> (2x - 3y)³
Therefore, by using the identity
{ (a - b)³ = a³ - b³ - 3a²b + 3ab²}
==> (2x - 3y)³ = (2x)³ - (3y)³ - 3(2x)²(3y) + 3(2x)(3y)²
==> 8x³ - 27y³ - 36x²y + 54xy²
==> 8x³ - 9y( 3y² - 4x² + 6xy)
➡Is the required answer.
****************************************************
HOPE IT HELPS YOU :)
#BEBRAINLY
#TOGETHER WE GO FAR
#☺☺☺
Here's your answer friend,
****************************************************
==> (2x - 3y)³
Therefore, by using the identity
{ (a - b)³ = a³ - b³ - 3a²b + 3ab²}
==> (2x - 3y)³ = (2x)³ - (3y)³ - 3(2x)²(3y) + 3(2x)(3y)²
==> 8x³ - 27y³ - 36x²y + 54xy²
==> 8x³ - 9y( 3y² - 4x² + 6xy)
➡Is the required answer.
****************************************************
HOPE IT HELPS YOU :)
#BEBRAINLY
#TOGETHER WE GO FAR
#☺☺☺
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