Question

factorise the expression : a²b+a²c+ab+ac+b²c+c²b explain step-by-step ​

Answer 1

Step-by-step explanation:

$a2b + a2c + ab + ac + b2c + c2b \\ a2(b + c) + a(b + c) + bc(b + c) \\ (b + c)(a2 + a + b)$

Answer 2

Answer:

(a²+a+bc) (b+c)

Explanation:

To factorise: a²b+a²c+ab+ac+b²c+c²b

We have to regroup these 6 terms into groups of 2

=(a²b+a²c) +(ab+ac) +(b²c+c²b)

=a²(b+c) + a(b+c) + bc(b+c)

We can see that (b+c) is common in all the terms, so, they will be one factor and leftovers will be the other!

=(a²+a+bc) (b+c)

This is The answer..I hope it helps!

Thank you