factorise the expression ax^+bx
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factorise the expression ax^²+bx
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Solution : (i) `ax^2 + bx` <br> `x(ax+b)` <br> (ii) `7p^2+ 21q^2` <br> `= 7(p^2 + 3q^2)` <br> (iii) `2x^3 + 2xy^2 + 2xz^2` <br> `2x(x^2 + y^2 + z^2)` <br> (iv) `am^2 + bm^2 + bn^2 + an^2` <br> `a(m^2+n^2)+ b(m^2+n^2)` <br> `(a+b)(m^2+ n^2)` <br> (v) `(lm+l)+m+l` <br> = `lm+l+m+l` <br> `= l(m+1)+1(m+1)` <br> `= (l+1)(m+1)` <br> (vi) `y(y+z)+ 9(y+z)` <br> `(y+9)(y+z)` <br> (vii)`5y^2 - 20y- 8z + 2yz` <br> `= 5y(y- 4) + 2z(y-4)` <br> `= (5y+2z)(y-4)` <br> (viii) `10ab +4a +5b+2` <br> `= 2a(5b+2)+1(5b+2)` <br> `=(2a+1)(5b+2)` <br> (ix) `6xy-4y+6-9x` <br> `= 2y(3x -2)-3(3x-2)` <br> `=(2y-3)(3x-2)` <br> answer
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Answer:
Factorising the expression
ax ^2 +bx
=x(ax+b)
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