Question

factorise the expression completely
x³+x²-4x-4
and
if 2(x-y)²=166 and xy=24, find the value of x²+y²​

Answer 1

Answer:

$x {}^{3} + x {}^{2} - 4x - 4 = 0 \\ = ( x = - 1)$

$2(x {}^{2} + y {}^{2} - 2xy) = 166 \\ x {}^{2} + y {}^{2} = \frac{166}{2} + 48 \\ = 83 + 48 = 131$