Question

factorise the expression- l²m²n-lm²n²+l²mn²​

Answer 1

Answer:

lmn(lm-mn+nl)

Step-by-step explanation:

This can be factorised by taking common only because mid-term breaking is not possible

Solution:-

l^2m^2n - lm^2n^2 + l^2mn^2

TAKING COMMON lmn

lmn (lm - mn + ln)

This is just like:--

A^2B + AB^2 = AB(A+B)

Please comment if u could not understand

Answer 2

Given,

Expression = l²m²n-lm²n²+l²mn²​

To Find.

Factorise the given expression =?

Solution,

Expression = l²m²n-lm²n²+l²mn²​

Factorising first term = l²m²n = l*l*m*m*n

Factorising second term = (-lm²n²) = (-1)*l*m*m*n*n

Factorising third term = l²mn²​ = l*l*m*n*n

The common factor in all terms = l*m*n

Taking lmn common in all terms in the expression, we get

Expression = lmn(lm - mn - ln)

Hence, the factorized expression of ²m²n-lm²n²+l²mn²​ is lmn(lm - mn - ln).