Question

Factorise the expression (x- 2y upon 3) cube

Answer 1

$Heya$‼

As we know,
$(a-b)^3=a^3-b^3-3ab(a-b)$

Now,
$(x-2y/3)^3$
$=(x)^3-(2y/3)^3-3(x)(2y/3)(x-2y/3)$
$=x^3-8y^3/27-2xy(x-2y/3)$
$=x^3-8y^3/27-2x^2y+4xy^2/3$

Answer 2

Heya User!! ✌

Here's your answer friend,

______________________________

✔ Using the identity
{(a - b)³ = a³ - b³ - 3a²b + 3ab²

We get,

==> (x - 2y/3)³ = x³ - (2y/3)³ - 3(x)²(2y/3) + 3(x)(2y/3)²

==> x³ - 8y³/27 - 2x²y + (4xy²/3)

➡Is the required answer.

↪ HOPE IT HELPS YOU :)

_______________________________

#BEBRAINLY
#TOGETHER WE GO FAR
#☺☺☺