Question

Factorise the expressions and divide them
1) 5 pq (p²_9²)÷2p (p+9)
2) (5pq²_25p÷20)÷(p_1)​

Answer 1

Answer:

1) $\frac{5q}{2} (p-9 )$

2) 5(p-4) (or) 5p-20

Step-by-step explanation:

1) 5 pq (p²_9²) ÷ 2p (p+9)

   = $\frac{5pq(p^2-9^2)}{2p(p+9)}$

   = $\frac{5*p*q* (p+9)(p-9) }{2*p*(p+9)}$

   =  $\frac{5*q* (p-9) }{2}$

   = $\frac{5q}{2} (p-9 )$

2) (5p²- 25p+20)÷(p_1)​

   = $\frac{5p^2-25p+20}{(p-1)}$

now consider, 5p²- 25p+20

                       = 5 (p²- 5p+4)

                       = 5 ( p²- 4p-p + 4 )

                       = 5 ( p (p- 4) - ( p - 4 ) )

 5p²- 25p+20 = 5 (p-4)(p-1)

$\frac{5p^2-25p+20}{(p-1)}$  = $\frac{5(p-4)(p-1)}{(p-1)}$

                 = 5(p-4)  (or) 5p-20