Question

Factorise the factors of 2y² - 4y - 30

Answer 1

ʜᴇʏ ᴍᴀᴛᴇ!!

ʜᴇʀᴇ's ᴜʀ ᴀɴsᴡᴇʀ ᴅᴇᴀʀ:-)
______________________

$2y {}^{2} - 4y - 30 \\ 2y {}^{2} -10y + 6y - 30 \\ 2y(y - 5) + 6(y - 5) \\ (y - 5)(2y + 6)$

______________________

ʜᴏᴘᴇ ɪᴛ ʜᴇʟᴘs ᴜ❤️❤️

☺️☺️☺️☺️

Answer 2

Answer:

2y² - 4y - 30 = 2(y+3)(y-5)

Step-by-step explanation:

2y² - 4y - 30

To factorise it we can use split method

we can get value -10 & 6  from which we get product = -60

& sum = -4

hence the equation can be written as

= 2y² - 10y + 6y - 30

now taking 2y common & 6 as common

= 2y(y-5) + 6(y-5)

now taking (y-5) as common

= (2y + 6)(y-5)

now taking two common from 2y + 6

= 2 (y+3)(y-5)

2y² - 4y - 30 = 2(y+3)(y-5)

Zeroes of 2y² - 4y - 30

2(y+3)(y-5) = 0

=> y = -3

& y = 5