Factorise the following
1) 16- p2-q2-2pq
Answers
Answered by
19
16 - p² - q² - 2pq
= 16 - ( p² + q² + 2pq )
= 4² - ( p + q )²
= [ 4+(p+q)][4-(p+k)]
= ( 4+p+q)(4-p-k)
Therefore,
16 - p² - q²-2pq=(4+p+q)(4-p-k)
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Answered by
3
Answer
=> 16-(p^2+q^2+2pq)
=>(4)^2 -(p+q)^2
=>[4+(p+q)][4-(p+q)]
=>(4+p+q)(4-p-q)
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