IF the G.P. of first six terms of any G.P is equal to 9 times the sum of first three terms then find the commen ratio of the G.P.
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Solution 1
Consider a GP as
a,ar,ar2,ar3,ar4,ar5a,ar,ar2,ar3,ar4,ar5
Sum of first 3 terms
=a+ar+ar2⋯(1)=a+ar+ar2⋯(1)
Sum of first 6 terms
=a+ar+ar2+ar3+ar4+ar5=a+ar+ar2+r3(a+ar+ar2)⋯(2)=a+ar+ar2+ar3+ar4+ar5=a+ar+ar2+r3(a+ar+ar2)⋯(2)
Let a+ar+ar2=xa+ar+ar2=x.
Then,
Sum of first 3 terms =x=x
Sum of first 6 terms =x+r3x=x(r3+1)=x+r3x=x(r3+1)
x(r3+1):x=9:1(r3+1):1=9:1r3+1=9r3=8r=2
Consider a GP as
a,ar,ar2,ar3,ar4,ar5a,ar,ar2,ar3,ar4,ar5
Sum of first 3 terms
=a+ar+ar2⋯(1)=a+ar+ar2⋯(1)
Sum of first 6 terms
=a+ar+ar2+ar3+ar4+ar5=a+ar+ar2+r3(a+ar+ar2)⋯(2)=a+ar+ar2+ar3+ar4+ar5=a+ar+ar2+r3(a+ar+ar2)⋯(2)
Let a+ar+ar2=xa+ar+ar2=x.
Then,
Sum of first 3 terms =x=x
Sum of first 6 terms =x+r3x=x(r3+1)=x+r3x=x(r3+1)
x(r3+1):x=9:1(r3+1):1=9:1r3+1=9r3=8r=2
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