Question

factorise the following
:10-7a-3a²

Answer 1

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$- {3a}^{2} - 7a + 10 = 0 \\ \\ - (3 {a}^{2} + 7a - 10) = 0 \\ \\ 3 {a}^{2} + 7a - 10 = 0 \\ \\ 3 {a}^{2} - 3a + 10a \: - 10 = 0 \\ \\ 3a(a - 1) + 10(a - 1) = 0 \\ \\ (a - 1)(3a + 10) = 0$



So the value of x = 1, -10/3



Thanks