Question

factorise the following 125 x square Y - 405 y cube​

Answer 1

Step-by-step explanation:

We need to factorise $125x^2y+405y^3$

 $125x^2y+405y^3$

=$5y(25x^2+81y^2)$

=$5y((5x+9y)^2-90xy)$

Answer:

$5y((5x+9y)^2-90xy)$

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