factorise the following
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1
Answer:
The factors are (x-1),(x-2),(x-3)
Step-by-step explanation:
=> x^3-6x^2+11x-6 (put x = 1)
=> P(x) = x^3 -6x^2+11x-6
=> P(1) = (1)^3-6(1)^2+11(1)-6
= -5+5
= 0
Hence, x=1
Therefore, x-1 =0
Now,
After Factorizing using remainder theorem we get x^2-5x+6
Therefore , We get => x^2-5x+6
=>x^2-3x-2x+6
=>x(x-3)-2(x-3)
=>(x-2) (x-3)
So, the factors are (x-1),(x-2),(x-3)
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2
Answer:
here is your answer dear
Step-by-step explanation:
❣hope it will help
❤please mark as brainlist
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