Factorise the following
2a^2-128a
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1
✶⊶⊷⊶⊷⊷⊶⊷ ❍⊷⊶⊷⊶⊷⊶⊷✶
2{(a)²-(8)²}
=2(a-8)(a+8)
so simple break it into a²-b²
✶⊶⊷⊶⊷⊷⊶⊷ ❍⊷⊶⊷⊶⊷⊶⊷✶
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aman6054:
By taking 2 as common,how u solved.
Answered by
6
Answer:
2 (a^2-64a)
2 {(a)^2-(8a^1/2)}
2 (a-8a^1/2)(a+8a^1/2)
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