Math, asked by Zerefgod202, 1 year ago

Factorise the following
2a^2-128a

Answers

Answered by Abhishek474241
1

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2{(a)²-(8)²}

=2(a-8)(a+8)

so simple break it into a²-b²

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aman6054: By taking 2 as common,how u solved.
renuanshayush123: by taking 2 i break the two numbers in the form of ^2-b^2
renuanshayush123: understand
Answered by renuanshayush123
6

Answer:

2 (a^2-64a)

2 {(a)^2-(8a^1/2)}

2 (a-8a^1/2)(a+8a^1/2)

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