factorise the following (2a+3b)^2-16c^2
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Answered by
37
Hey mate!!
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(2a + 3b)² - 16c²
=> (2a + 3b)² - (4c)²
Using identity :
x² - y² = (x + y)(x - y)
=> (2a + 3b)² - (4c)²
=> (2a + 3b + 4c)(2a + 3b - 4c)
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Thanks for the question!!
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(2a + 3b)² - 16c²
=> (2a + 3b)² - (4c)²
Using identity :
x² - y² = (x + y)(x - y)
=> (2a + 3b)² - (4c)²
=> (2a + 3b + 4c)(2a + 3b - 4c)
=======================
Thanks for the question!!
Answered by
14
heya ☺☺☺
(2a + 3b)2 - 16c2
= 4a2 + 9b2 - 12ab - 16c2
=4a2 + 9b2 - 16c2 + 12ab...
I hope it help's u...✌✌✌
(2a + 3b)2 - 16c2
= 4a2 + 9b2 - 12ab - 16c2
=4a2 + 9b2 - 16c2 + 12ab...
I hope it help's u...✌✌✌
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