Question

factorise the following 2a+6b-3(a+3b)^2

Answer 1

2a+6b-3(a+3b)²,

2(a+3b)-3(a+3b)²,

(a+3b)[2-3(a+3b)],

Answer 2

HERE IS YOUR ANSWER...⬇⬇

$\red{\underline{SOLUTION}}$ ➡

$2a + 6b - 3(a + 3b) {}^{2} \\ \\ = 2(a + 3b) - 3(a + 3b) {}^{2} \\ \\ = (a + 3b)(2 -3(a + 3b)) \\ \\ = (a + 3b) (2 - 3a + 9b)$

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