Math, asked by khushi2005, 11 months ago

factorise the following

2a²c + 2b²c + ab + 4abc2 + ab + 4abc2
2

Answers

Answered by rudrakshmohanty05

0

Answer:2(a^2 c+b^2 c+ab+48abc)

Step-by-step explanation:

=>2a^2 c+2b^2 c+2ab+8abc+88abc

=>2a^2 c+2b^2 c+2ab+96abc

=>2(a^2 c+b^2 c+ab+48abc)

Answered by AyushSingh1525

0

=2a^2 c+2b^2 c+2ab+8abc+88abc

=2a^2 c+2b^2 c+2ab+96abc

=2(a^2 c+b^2 c+ab+48abc)

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