factorise the following
2a²c + 2b²c + ab + 4abc2 + ab + 4abc2
2
Answers
Answered by
0
Answer:2(a^2 c+b^2 c+ab+48abc)
Step-by-step explanation:
=>2a^2 c+2b^2 c+2ab+8abc+88abc
=>2a^2 c+2b^2 c+2ab+96abc
=>2(a^2 c+b^2 c+ab+48abc)
Answered by
0
=2a^2 c+2b^2 c+2ab+8abc+88abc
=2a^2 c+2b^2 c+2ab+96abc
=2(a^2 c+b^2 c+ab+48abc)
Similar questions