Two resistor 4 and 6 ohm connected in parallel to a battery of 6 v of negligeable resistance calculate current through a battery
Answers
Answered by
7
Total Resistance of the circuit
1/R = 1/4 + 1/6
1/R = (6+4)/24
1/R = 10/24
R = 24/10
R = 2.4 ohms
V = 6 volts
V = IR
6 = I * (2.4)
I = 6/2.4
I = 2.5 ampere
1/R = 1/4 + 1/6
1/R = (6+4)/24
1/R = 10/24
R = 24/10
R = 2.4 ohms
V = 6 volts
V = IR
6 = I * (2.4)
I = 6/2.4
I = 2.5 ampere
Answered by
1
6 / (( 4 * 6) / 6+4 ) = (6 * 10) / 24 = 2.5A
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