Question

Factorise the following: 2x^2+3x-6

Answer 1

Answer:

a=2,b=3,c=-6

D=b^2-4ac

=(3)^2-4*2*-6

=9-48

D=-39

D<0

therefore, roots will not existed

I hope you understand

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Answer 2

Answer:

=x^3-12

Step-by-step explanation:

=2x^2+3x-6

=2*x^2+3*x-2*3

=2*x^2+x^1+3-2*3

=2*x^3-6

=x^3-12(2 and -6 are multiplied)