Math, asked by savitasingh1031, 6 months ago

factorise the following (3a-1)^2-6a+2​

Answers

Answered by payalkarn
2

Answer:

(3a-1)(a-1)

Step-by-step explanation:

(3a-1)^2-6a+2

(a-b)^2 = a^2+b^2 -2ab

(3a)^2 + (1)^2 -2×3a×1 -6a +2

9a^2 +1 -6a-6a +2

9a^2 - 12a +3

take 3 as common

3a^2 - 4a +1

3a^2 -3a - a+1

3a(a-1) -1(a-1)

(3a -1)(a-1)

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