Question

factorise the following 4a2 -9b2 - 2a - 3b​

Answer 1

Step-by-step explanation:

4a

2

+4ab−4ca

The common factor =2×2×a

Thus, 4a

2

+4ab−4ca

=4a(a+b−c)

Answer 2

Answer:

Question :-

➠ 4a² - 9b² - 2a - 3b

Formula used :-

➪ a² - b²

➭ (a + b) (a - b)

Answer :-

➠ 4a² - 9b² - 2a - 3b

➻ (2a)² - (3b)² - (2a + 3b)

➻ (2a + 3b) (2a - 3b) - (2a + 3b)

➻ (2a + 3b) {(2a - 3b) - 1} [Taking 2a + 3b common]

➻ (2a + 3b) (2a - 3b - 1)

∴ The value of 4a² - 9b² - 2a - 3b is (2a + 3b) (2a - 3b - 1)