Question

Factorise the following:-
81a⁴​- p⁴​




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Answer 1

Answer:

4=(p2)2 and 256=(16)2

4=(p2)2 and 256=(16)2Thus p4−256=(p2)2−(16)2

4=(p2)2 and 256=(16)2Thus p4−256=(p2)2−(16)2=(p2−16)(p2+16)           [∵p2−16=(p+4)(p−4)]

4=(p2)2 and 256=(16)2Thus p4−256=(p2)2−(16)2=(p2−16)(p2+16)           [∵p2−16=(p+4)(p−4)]=(p+4)(p−4)(p2+16)

Step-by-step explanation:

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Answer 2

Answer:

(a+b) (a-b)

(9a +p) ( 9a - p )

9a (9a-p) +p(9a-p)

81a² - 9ap + 9ap - p²

= 81a² - p²

Step-by-step explanation:

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