factorise the following: 81x³-3y³
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Here's your answer;
We are given an equation to factorise, which is as follows:
81x³ - 3y³
Now, we know that the following equation can also be written as,
81x³ - 3y³ = 3( 27x³ - y³ )
Now, solving RHS,
= 3 [ (3x)³ - (y)³ ]
Using the Identity, a³ - b³ = ( a - b ) ( a² + ab + b² )
⇒ 3 [ (3x - y) ( (3x)² + 3xy + y²) ]
Or,
81x³ - 3y³ = 3 [ (3x - y) ( 9x² + 3xy + y² ) ]
Hope, this helps.
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