Question

factorise the following 9a^2- (2a - b) ^2
Step pls
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Answer 1

{9a^2-(2a)^2+(b)^2-2×2a×b}

{9a^2-2a^2+b^2-4ab}

5a^2+b^2-4ab

Answer 2

Step-by-step explanation:

$= 9 {a}^{2} - {(2a - b)}^{2}$

$= 9 {a}^{2} - (4 {a}^{2} + {b}^{2} - 4ab)$

$= 9 {a}^{2} - 4 {a}^{2} - {b}^{2} + 4ab$

$= 5 {a}^{2} + 4ab - {b}^{2}$

$= 5 {a}^{2} + 5ab - ab - {b}^{2}$