Factorise the following
a) 64x3y3+27z3
Answers
Answered by
2
64x³y³+27z³ {Given}
Forming Cubes we get,
⇒ (4xy)³ + (3z)³
[.·. a³+b³= (a+b) (a²+b²-ab) ]
⇒(4xy+3z)(16x²y²+9z²-12xyz)
Forming Cubes we get,
⇒ (4xy)³ + (3z)³
[.·. a³+b³= (a+b) (a²+b²-ab) ]
⇒(4xy+3z)(16x²y²+9z²-12xyz)
Answered by
1
According to the given question;
64x³y³+27z³
=(4xy)³+(3z)³ [4³=64 and 3³=27]
=(4xy +3z)[16x²y²+9z²-12xyz]
This cannot be simplified further....no like terms.....
hope i helped u:)
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tithi:
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