Question

factorise the following.
(a + b)² – (a - b)²​

Answer 1

4ab

Step-by-step explanation:

a^2 + b^2 + 2ab -(a^2+ b^2 -2ab)

a^2 + b^2 + 2ab -a^2 -b^2 + 2ab

a^2-a^2 +b^2 -b^2 +2ab + 2ab

4ab

Answer 2

Answer:

• Factorise value is 4ab.

Step-by-step explanation:

As we know that,

$\: \: \sf \rightarrow \: {(a + b)}^{2} = {(a)}^{2} + {(b)}^{2} + 2ab$

$\: \: \sf \rightarrow \: {(a - b)}^{2} = {(a)}^{2} + {(b)}^{2} - 2ab$

Now after knowing the formula let's find the factorise value

According to the question,

$\: \: \sf \: {(a + b)}^{2} - {(a - b)}^{2} \\ \\ \: \: \sf \: ( {a}^{2} + {b}^{2} + 2ab) - ( {a}^{2} + {b}^{2} - 2ab) \\ \\ \: \: \sf \: {a}^{2} + {b}^{2} + 2ab - {a}^{2} - {b}^{2} + 2ab \\ \\ \: \: \sf \: \cancel{a}^{2} - \cancel {a}^{2} + \cancel {b}^{2} - \cancel {b}^{2} + 2ab + 2ab \\ \\ \: \: \sf \dagger \: \therefore \: 4ab$