factorise the following:(a+b)³ - (a-b)³
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hey here is your answer
Expanding:
(a+b)3−(a−b)3
=(a3+3a2b+3ab2+b3)−(a3−3a2b+3ab2−b3)
=6a2b+2b3
=2b(3a2+b2)
If you are allowed complex coefficients this can be broken down into linear factors:
=2b(√3a+ib)(√3a−ib)
Notice also that:
(a+b)3+(a−b)3=(b+a)3−(b−a)3=2a(3b2+a2)
make sure it brainliest please
Expanding:
(a+b)3−(a−b)3
=(a3+3a2b+3ab2+b3)−(a3−3a2b+3ab2−b3)
=6a2b+2b3
=2b(3a2+b2)
If you are allowed complex coefficients this can be broken down into linear factors:
=2b(√3a+ib)(√3a−ib)
Notice also that:
(a+b)3+(a−b)3=(b+a)3−(b−a)3=2a(3b2+a2)
make sure it brainliest please
sweetandsimple64:
make sure it brainliest please
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