Factorise the following algebraic expression by using suitable identity : a²x²–25.
Answers
Answered by
6
Answer:
(ax+5)(ax-5)
Step-by-step explanation:
- a²x²-25
- (ax)²-(5)²
- (ax+5)(ax-5) [using the identity x²-y²=(x+y)(x-y)]
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Answered by
3
Answer:
(ax+5)(ax-5)
Step-by-step explanation:
a²x²_25
(ax)²_(5)²
the identity is a²_b²=(a+b) (a_b)
(ax+5) (ax_5)
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