Factorise the following by regrouping the terms.
a) 6xy-y^2+12xz-2yz
b) b^2-ab(1-a)-a^3
c) a^2-a(x+2y)+2xy
d) x^3-2x^2y+3xy^2-6y^3
e) xy(a^2+1)-a(x^2+y^2)
Answers
Question :-
Factorise the following by regrouping the terms.
a) 6xy - y² + 12xz - 2yz
b) b² - ab(1 - a) - a³
c) a² - a(x + 2y) + 2xy
d) x³ - 2x²y + 3xy² - 6y³
e) xy(a² + 1)-a(x² + y²)
Solution :-
a)
◘ The factorised form is (6x - y)(y + 2z).
_________________
b)
◘ The factorised form is (b - a)(b + a²).
_________________
c)
◘ The factorised form is (a - x)(a - 2y).
_________________
d)
◘ The factorised form is (x - 2y)(x² + 3y²).
_________________
e)
◘ The factorised form is (ax - y)(ay - x).
Step-by-step explanation:
Factorise the following by regrouping the terms.
a) 6xy - y² + 12xz - 2yz
b) b² - ab(1 - a) - a³
c) a² - a(x + 2y) + 2xy
d) x³ - 2x²y + 3xy² - 6y³
e) xy(a² + 1)-a(x² + y²)
\huge \sf {\orange {\underline {\pink{\underline{Solution :-}}}}}
Solution:−
a) \sf{6xy-y^2+12xz-2yz}6xy−y
2
+12xz−2yz
\sf{= y(6x-y)+2z(6x-y) }=y(6x−y)+2z(6x−y)
\sf{= (6x-y)(y+2z)}=(6x−y)(y+2z)
◘ The factorised form is (6x - y)(y + 2z).
_________________
b) \sf{ b^2-ab(1-a)-a^3}b
2
−ab(1−a)−a
3
\sf{=b^2-ab+a^2b-a^3 }=b
2
−ab+a
2
b−a
3
\sf{=b(b-a)+a^2(b-a)}=b(b−a)+a
2
(b−a)
\sf{=(b-a)(b+a^2)}=(b−a)(b+a
2
)
◘ The factorised form is (b - a)(b + a²).
_________________
c) \sf{a^2-a(x+2y)+2xy}a
2
−a(x+2y)+2xy
\sf{=a^2-ax-2ay+2xy }=a
2
−ax−2ay+2xy
\sf{= a(a-x)-2y(a-x)}=a(a−x)−2y(a−x)
\sf{= (a-x)(a-2y)}=(a−x)(a−2y)
◘ The factorised form is (a - x)(a - 2y).
_________________
d) \sf{x^3-2x^2y+3xy^2-6y^3}x
3
−2x
2
y+3xy
2
−6y
3
\sf{=x^2(x-2y)+3y^2(x-2y) }=x
2
(x−2y)+3y
2
(x−2y)
\sf{= (x-2y)(x^2+3y^2)}=(x−2y)(x
2
+3y
2
)
◘ The factorised form is (x - 2y)(x² + 3y²).
_________________
e) \sf{xy(a^2+1)-a(x^2+y^2)}xy(a
2
+1)−a(x
2
+y
2
)
\sf{= a^2xy+xy-ax^2-ay^2}=a
2
xy+xy−ax
2
−ay
2
\sf{=a^2xy - ax^2 + xy - ay^2}=a
2
xy−ax
2
+xy−ay
2
\sf{=ax(ay-x)-y(ay-x)}=ax(ay−x)−y(ay−x)
\sf{=( ax - y )( ay - x )}=(ax−y)(ay−x)
◘ The factorised form is (ax - y)(ay - x).
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