Factorise the following by splitting the middle term.
Attachments:
Answers
Answered by
1
Answer:
(E) 4x²+16x+15
= 4x²+6x+10x+15
= 2x(2x+3) + 5(2x+3)
= (2x+3)(2x+5)
(F) 4x²+4x-15
= 4x²-6x+10x-15
= 2x(2x-3) + 5(2x-3)
= (2x+5)(2x-3)
(G) 4x²-4x-15
= 4x²-10x+6x-15
= 2x(2x-5) + 3(2x-5)
= (2x+3)(2x-5)
(H) 4x²-16x+15
= 4x²-6x-10x+15
= 2x(2x-3)-5(2x-3)
= (2x-5)(2x-3)
Answered by
1
E. 4x²+10x + 6x + 15
2x(2x+5) + 3(2x+5)
(2x+5) (2x+3)
F. 4x²+ 10x - 6x - 15
2x( 2x+5) - 3 (2x +5)
( 2x-3) (2x+5)
G. 4x² + 6x - 10x - 15
2x( 2x+3) -5 ( 2x +3)
( 2x-5) ( 2x +3)
H. 4x² -10x -6x + 15
2x(2x - 5) - 3 (2x -5)
(2x-3) (2x-5)
Similar questions