Question

factorise the following by suitable identities.​

Answer 1

(b) 4y²+4y+1

4y²+2y+2y+1

2y(2y+1)+1(2y+1)

(2y+1)(2y+1)

(2y+1)

(c) p²-22pq+121q²

p²-11pq-11pq+121q²

p(p-11q) -11q(p-11q)

(p-11q) (p-11)

(p-11)

Answer 2

Answer:

b. 4y² + 4y + 1

= (2y)² + 2 (2y × 1) + (1)²

= (2y + 1)²

OR

b. 4y² + 4y + 1

= 4y² + 2y + 2y + 1

= 2y (2y + 1) + 1 (2y + 1)

= (2y + 1) (2y + 1)

= (2y + 1)²

e. p² - 22pq + 121q²

= (p)² - 2(p × 11q) + (11q)²

= (p - 11q)²

OR

e. p² - 22pq + 121q²

= p² - 11pq - 11pq + 121q²

= p (p - 11q) - 11q (p - 11q)

= (p - 11q) (p - 11q)

= (p - 11q)²

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