Math, asked by mdsahbaz9231, 2 months ago

factorise the following by taking out the common factor:- please answer it then I mark as brainlist ​

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Answers

Answered by yogeshbhuyal7
0

OVERVIEW

SIMPLIFY

QUESTION

5y^{3}(x^{2}-5)-2y^{2}(x^{2}-5)+3y(x^{2}-5)5y

3

(x

2

−5)−2y

2

(x

2

−5)+3y(x

2

−5)

STEPS TO SOLVE

1

Distribute

{\color{#c92786}{5x^{2}y^{3}-25y^{3}}}-2y^{2}(x^{2}-5)+3y(x^{2}-5)5x

2

y

3

−25y

3

−2y

2

(x

2

−5)+3y(x

2

−5)

2

Distribute

5x^{2}y^{3}-25y^{3}{\color{#c92786}{-2x^{2}y^{2}+10y^{2}}}+3y(x^{2}-5)5x

2

y

3

−25y

3

−2x

2

y

2

+10y

2

+3y(x

2

−5)

3

Distribute

5x^{2}y^{3}-25y^{3}-2x^{2}y^{2}+10y^{2}+{\color{#c92786}{3yx^{2}-15y}}5x

2

y

3

−25y

3

−2x

2

y

2

+10y

2

+3yx

2

−15y

4

Rearrange terms

{\color{#c92786}{5x^{2}y^{3}-2x^{2}y^{2}-25y^{3}+3yx^{2}+10y^{2}-15y}}5x

2

y

3

−2x

2

y

2

−25y

3

+3yx

2

+10y

2

−15y

SOLUTION

5x^{2}y^{3}-2x^{2}y^{2}-25y^{3}+3yx^{2}+10y^{2}-15y5x

2

y

3

−2x

2

y

2

−25y

3

+3yx

2

+10y

2

−15y

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