Question

factorise the following by using a suitable identity : 2a raise to5 - 54a raise to 2

Answer 1

2a^5 - 54 a^2

take 2a^2 common we get

=2 a^2 ( a^3 - 27 )

= 2 a^2 [ a^3 - 3^3]

use the identity x^3 - y^3 = ( x - y ) ( x^2 + xy + y^2 ) we get

= 2 a^3 ×( a - 3 ) ( a^2 + 3a + 3^2 )

= 2 a ^3×(a - 3) ( a^2 + 3a + 9)

i hope this will useful to u

Answer 2

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