factorise the following by using a suitable identity : 2a raise to5 - 54a raise to 2
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2a^5 - 54 a^2
take 2a^2 common we get
=2 a^2 ( a^3 - 27 )
= 2 a^2 [ a^3 - 3^3]
use the identity x^3 - y^3 = ( x - y ) ( x^2 + xy + y^2 ) we get
= 2 a^3 ×( a - 3 ) ( a^2 + 3a + 3^2 )
= 2 a ^3×(a - 3) ( a^2 + 3a + 9)
i hope this will useful to u
take 2a^2 common we get
=2 a^2 ( a^3 - 27 )
= 2 a^2 [ a^3 - 3^3]
use the identity x^3 - y^3 = ( x - y ) ( x^2 + xy + y^2 ) we get
= 2 a^3 ×( a - 3 ) ( a^2 + 3a + 3^2 )
= 2 a ^3×(a - 3) ( a^2 + 3a + 9)
i hope this will useful to u
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2 a^3 ×( a - 3 ) ( a^2 + ab + b^2 )
I think 'b' should be replaced by 3
I think 'b' should be replaced by 3
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